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api: Don't silently fail apiserver instance initialization
- ApiServer instance assumes cloudstartup servlet will initialize it - Check and log if initialization fails Signed-off-by: Rohit Yadav <bhaisaab@apache.org>
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@ -121,7 +121,6 @@ import com.cloud.utils.exception.CSExceptionErrorCode;
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import com.cloud.uuididentity.dao.IdentityDao;
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import com.cloud.acl.APIAccessChecker;
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public class ApiServer implements HttpRequestHandler {
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private static final Logger s_logger = Logger.getLogger(ApiServer.class.getName());
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private static final Logger s_accessLogger = Logger.getLogger("apiserver." + ApiServer.class.getName());
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@ -143,7 +142,6 @@ public class ApiServer implements HttpRequestHandler {
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private static ExecutorService _executor = new ThreadPoolExecutor(10, 150, 60, TimeUnit.SECONDS, new LinkedBlockingQueue<Runnable>(), new NamedThreadFactory("ApiServer"));
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private ApiServer() {
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}
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@ -155,11 +153,14 @@ public class ApiServer implements HttpRequestHandler {
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}
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public static ApiServer getInstance() {
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// initApiServer();
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// Assumption: CloudStartupServlet would initialize ApiServer
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// initApiServer(null);
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if (s_instance == null) {
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s_logger.fatal("ApiServer instance failed to initialize");
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}
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return s_instance;
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}
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public void init(String[] apiConfig) {
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BaseCmd.setComponents(new ApiResponseHelper());
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BaseListCmd.configure();
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@ -908,7 +909,6 @@ public class ApiServer implements HttpRequestHandler {
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public String getSerializedApiError(int errorCode, String errorText, Map<String, Object[]> apiCommandParams, String responseType, Exception ex) {
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String responseName = null;
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String cmdClassName = null;
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String responseText = null;
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try {
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